Function std::boxed::into_raw
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[src]
pub fn into_raw<T>(b: Box<T>) -> *mut T where T: ?Sized: may be renamed
Consumes the Box, returning the wrapped raw pointer.
After call to this function, caller is responsible for the memory
previously managed by Box, in particular caller should properly
destroy T and release memory. The proper way to do it is to
convert pointer back to Box with Box::from_raw function, because
Box does not specify, how memory is allocated.
Examples
#![feature(alloc)] fn main() { use std::boxed; let seventeen = Box::new(17u32); let raw = boxed::into_raw(seventeen); let boxed_again = unsafe { Box::from_raw(raw) }; }use std::boxed; let seventeen = Box::new(17u32); let raw = boxed::into_raw(seventeen); let boxed_again = unsafe { Box::from_raw(raw) };